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Q&A Matriz do operador derivada

$D = \begin{bmatrix} 0 & 1 & 0 & 0 \\ 0 & 0 & 2 & 0 \\ 0 & 0 & 0 & 3 \\ 0 & 0 & 0 & 0 \end{bmatrix}$

posted 7d ago by Rodolfo Broco Manin‭

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#1: Initial revision by user avatar Rodolfo Broco Manin‭ · 2024-10-14T15:47:30-03:00 (7 days ago) 
$D = \begin{bmatrix} 0 & 1 & 0 & 0 \\ 0 & 0 & 2 & 0 \\ 0 & 0 & 0 & 3 \\ 0 & 0 & 0 & 0 \end{bmatrix}$